Discussion
An amplifier of \( 1 \ \mathrm{MHz} \) gain-bandwidth product is used at a closed-loop gain of \( 5 \). Its bandwidth is
Answer: D
Dividing the product by the closed-loop gain:
\[ B = \frac{10^{6}}{5} = 200 \ \mathrm{kHz} \]
giving 200 kHz. Multiplying gives five megahertz, more bandwidth than the amplifier possesses at any gain, which is a useful check on the direction. This one division is the calculation behind every operational amplifier selection, and it is why the product rather than either factor is the figure quoted.
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