Discussion
An amplifier with \( 5 \ \mathrm{Hz} \) open-loop bandwidth is closed with a loop gain of \( 1999 \). Its bandwidth becomes
Answer: A
Bandwidth rises by one plus the loop gain:
\[ B_{f} = 5 \times 2000 = 10 \ \mathrm{kHz} \]
giving 10 kHz. A five hertz open-loop bandwidth sounds useless until the loop gain is applied, which is exactly the situation inside every internally compensated operational amplifier: enormous gain over a tiny bandwidth, traded for modest gain over a useful one.
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