Discussion
Why can a capacitive load destabilise a feedback amplifier?
Answer: A
The load works against the output impedance to form an extra pole, and since the output is inside the feedback loop that pole's phase is added to the loop's own. It does not change the low-frequency loop gain or the fraction, and the input is unaffected. Anything that adds phase shift inside a loop eats into its margin, whether it was part of the design or attached afterwards, which is why load conditions belong in a stability specification. The quantity that varies and the quantity that does not are worth naming before any substitution is attempted.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development