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Why does an amplifier's slew rate limit its large-signal bandwidth?

  • A.The devices saturate at high frequencies and stop amplifying
  • B.The feedback fraction falls as the output amplitude grows
  • C.The open-loop gain drops as the output approaches the rails
  • D.The compensation capacitor charges at a fixed maximum rate

Answer: D

The internal compensation capacitor is charged from a limited current, so the output cannot change faster than that current divided by the capacitance, whatever the small-signal bandwidth suggests. It is a large-signal limit quite separate from the small-signal roll-off, and a sine wave of large amplitude can trigger it well inside the nominal bandwidth. That two independent limits govern the same amplifier, one for small signals and one for large, is why both are specified and why exceeding either produces quite different distortion.

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