Discussion
What is a common-source stage's voltage gain?
Answer: B
The gain is minus the transconductance times the drain load, exactly parallel to the bipolar case but with a much smaller transconductance, so the gains are correspondingly modest - tens rather than hundreds. The second option is the degenerated form. The parallel with the bipolar expression is worth noticing, since it means the same intuitions about loading and degeneration apply unchanged. Framing the question as which quantity the change acts upon makes the answer follow without calculation.
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