Discussion
A stage has \( g_{m} = 3 \ \mathrm{mS} \) and \( R_{D} = 4.7 \ \mathrm{k\Omega} \). Its gain is about
Answer: C
Multiplying transconductance by load:
\[ A_{v} = -0.003 \times 4700 \approx -14 \]
giving about -14, an order of magnitude less than a bipolar stage with the same load resistor. That modest figure is the price of the enormous input impedance, and it is why field effect input stages are usually followed by bipolar gain rather than being asked to provide it all. Reading the definition literally, rather than recalling a formula, is the reliable route through questions of this shape.
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