Discussion
A source follower has \( g_{m} = 4 \ \mathrm{mS} \) and \( R_{S} = 1 \ \mathrm{k\Omega} \). Its gain is about
Answer: D
The follower's gain uses the same degeneration factor:
\[ \begin{aligned} A_{v} &= \frac{0.004 \times 1000}{1 + 0.004 \times 1000} \\ &= 0.8 \end{aligned} \]
giving 0.8, noticeably below an emitter follower's 0.99 because the transconductance is ten times smaller. A gain above one is impossible, which rules out 1.25 immediately. Unity is a limit these followers approach far less closely than their bipolar counterparts.
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