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Why does a common-gate stage have a wide bandwidth?

  • A.Its transconductance rises with frequency in that arrangement
  • B.No inverting gain bridges its input and output
  • C.Its gate capacitance is smaller than in other configurations
  • D.Its input impedance is low enough to swamp all capacitance

Answer: B

With the gate common, the gate-drain capacitance no longer bridges input and output across an inverting gain, so there is no Miller multiplication - precisely the common-base argument. The capacitance itself is a device property unchanged by configuration, and the transconductance does not rise with frequency. Bandwidth is about which capacitance sees which gain, in either device family.

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