Discussion
Doubling that current changes the conduction loss to
Answer: D
The loss goes as the square of the current:
\[ P = 400 \times 0.02 = 8 \ \mathrm{W} \]
so 8 watts, four times the original rather than twice. Four watts would be the answer if the loss were proportional to current, which is the bipolar saturation-voltage case rather than this one. The order of a loss law decides how a design scales, and a quadratic law means headroom disappears far faster than intuition suggests as the current rating is approached.
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