Discussion
Estimate VGS in the following circuit :
(Figure: an n-channel MOSFET whose gate and drain are both connected to the 5 V supply; its source is connected to ground through a 7 K resistor, and a current of 0.3 mA flows down through that resistor.)
Answer: D
\(V_{GS}\) is about 2.9 V.
The gate is tied to the 5 V supply, so \(V_{G} = 5\) V. The source voltage is the drop across the 7 K resistor carrying 0.3 mA.
\[ \begin{aligned} V_{S} &= 0.3\ \text{mA} \times 7\ \text{k}\Omega = 2.1\ \text{V} \\ V_{GS} &= V_{G} - V_{S} = 5 - 2.1 = 2.9\ \text{V} \end{aligned} \]
The other values would need different source voltages: 4.9 V a drop of only 0.1 V across the resistor, 3.5 V a drop of 1.5 V, and 1.5 V a drop of 3.5 V. None matches 0.3 mA through 7 kΩ.
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