Discussion
At 3072 bits per second, 25 hours of recording requires approximately
Answer: D
Correct answer: 276 megabits
Multiply the rate by the number of seconds:
\[ 25 \times 3600 = 90\,000\ \mathrm{s} \]
\[ 3072 \times 90\,000 = 2.765 \times 10^{8}\ \mathrm{bits} \approx 276\ \mathrm{Mbit} \]
That is about 35 megabytes for 25 hours of flight data - a figure that made magnetic tape a genuine constraint and makes solid-state memory trivially adequate. The capacity limit that once shaped the parameter list has simply disappeared.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development