Discussion
A receiver tuned to \( 98.1 \ \mathrm{MHz} \) with high-side injection has its oscillator at
Answer: C
Adding the intermediate frequency:
\[ f_{LO} = 98.1 + 10.7 = 108.8 \ \mathrm{MHz} \]
giving 108.8 MHz, just above the top of the broadcast band. 87.4 MHz is low-side injection, which would place the oscillator inside the band and risk radiating into it. 98.1 MHz is the signal and 10.7 MHz the intermediate frequency. Keeping the oscillator out of the received band is one practical reason high-side injection is preferred here. Working one numerical case through both schemes side by side fixes the distinction better than any rule of thumb.
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