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Why does an emitter bypass capacitor break at a much higher frequency than a coupling capacitor of the same value?

  • A.It works into a far lower resistance
  • B.It carries a much larger signal current
  • C.It has a lower reactance at every frequency
  • D.It is in parallel rather than in series with the signal

Answer: A

The resistance at the emitter is the degeneration resistor in parallel with the small intrinsic emitter resistance, often only tens of ohms, so the same capacitance gives a break hundreds of times higher. Its reactance at a given frequency is identical, being the same capacitance, and the parallel connection is why it sees that low resistance rather than being the reason directly. A time constant is a product, so a small resistance forces a large capacitance if a low break is wanted.

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