Discussion
An emitter bypass works into \( 30 \ \Omega \). For a \( 20 \ \mathrm{Hz} \) break it must be at least about
Answer: B
The same relation with the far smaller resistance:
\[ C = \frac{1}{2\pi (20)(30)} \approx 265 \ \mathrm{\mu F} \]
giving about 265 microfarads, five hundred times the coupling capacitor's value for the same frequency. That contrast is why the emitter bypass is invariably the largest capacitor in a small-signal stage, and usually the one that decides where the response actually starts to fall.
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