Discussion
Why is a common-base stage's input capacitance small?
Answer: C
Driving the emitter means the collector-base capacitance does not bridge input and output at all, so no multiplication occurs and the input capacitance is the emitter junction's alone. The bypassed base is how that isolation is achieved rather than the reason directly. Junction bias and transconductance are the same as in any configuration at the same operating point. Which terminal is the input decides which capacitances bridge the stage, and that decides the bandwidth.
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