Discussion
A follower's output looks inductive at \( 500 \ \mathrm{nH} \) into a \( 100 \ \mathrm{pF} \) load. The resonance is near
Answer: C
Applying the resonant frequency of the pair:
\[ \begin{aligned} f &= \frac{1}{2\pi\sqrt{LC}} \\ &= \frac{1}{2\pi\sqrt{5\times10^{-17}}} \end{aligned} \]
which gives about 22 MHz. The other options misplace a decade or two. Because the frequency depends on the square root of the product, a hundredfold change in either component moves it only tenfold, which is why such resonances are hard to shift out of the way and are better damped than avoided.
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