Discussion
Why does a cascode's upper device not suffer a Miller penalty of its own?
Answer: D
The upper device is a common-base stage, so its input is its emitter and its collector-base capacitance does not bridge input to output. Its capacitance is the same device property, its base is bypassed rather than driven, and it does take substantial voltage gain. The cascode works because neither device presents a multiplied capacitance: the lower has no gain and the upper has no bridging path, which is why the combination beats either configuration alone.
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