Discussion
A cable of \( 100 \ \mathrm{pF} \) loads a stage whose output impedance is \( 2 \ \mathrm{k\Omega} \). The break is at about
Answer: A
The output impedance works into the cable capacitance:
\[ \begin{aligned} f &= \frac{1}{2\pi (2000)(100 \times 10^{-12})} \\ &\approx 800 \ \mathrm{kHz} \end{aligned} \]
so about 800 kHz. Driving the same cable from sixty ohms would move the break to twenty-six megahertz, which is why a follower or a line driver is fitted whenever a cable has to be driven. The cable is the same; the difference is entirely in what drives it.
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