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In a multiple disc clutch, n1 and n2 are the number of discs on the driving shafts respectively. The number of pairs of disc on the drive shaft is :

  • A.\(\frac{n_{1} + n_{2}}{2}\)
  • B.\(n_{1} + n_{2}\)
  • C.\(n_{1} + n_{2} - 1\)
  • D.\(n_{1} + n_{2} + 1\)

Answer: C

The number of pairs is \(n_1 + n_2 - 1\).

In a multiple disc clutch, discs on the driving shaft alternate with discs on the driven shaft. Every adjacent pair of discs forms one pair of contact surfaces, and with \(n_1 + n_2\) discs stacked alternately there is one fewer interface than there are discs:

\[ n = n_1 + n_2 - 1 \]

The torque transmitted is proportional to this number. \(n_1 + n_2\) counts the discs, not the pairs, \(n_1 + n_2 + 1\) overcounts further, and \(\frac{n_1 + n_2}{2}\) would treat each disc as pairing with only one other.

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