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The oxygen required to burn 1 kg of sulphur to sulphur dioxide is

  • A.1 kg
  • B.2 kg
  • C.0.5 kg
  • D.2.67 kg

Answer: A

Correct answer: 1 kg

The reaction is \( \mathrm{S} + \mathrm{O_2} \rightarrow \mathrm{SO_2} \), so 32 kg of sulphur takes 32 kg of oxygen and the ratio is \[ \frac{32}{32} = 1\ \text{kg of oxygen per kg of sulphur.} \] Sulphur is usually a small fraction of the fuel, so its contribution to the air requirement is minor - it matters far more for corrosion and for the sulphur dioxide in the flue gas.

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