Discussion
What is the output of this C code?
void foo();
int main()
{
void foo(int);
foo(1);
return 0;
}
void foo(int i)
{
printf("2 ");
}
Answer: A
Correct answer: 2
The declaration inside main - void foo(int) - is the one in scope at the call, so foo(1) matches it, and it agrees with the definition. The outer void foo() declares a function with an unspecified parameter list rather than none, so it does not conflict. The program prints 2.
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