Machine-translated by Google. Questions are authored in English.
Top

Discussion

For steady one-dimensional flow, the mass flow rate through a duct is given by

  • A.Density divided by the product of area and velocity
  • B.Area times velocity divided by the density
  • C.The sum of the density, the area and the velocity
  • D.Density times area times velocity

Answer: D

The product rho times A times V has the units of mass per unit time and is constant along the duct for steady flow. For incompressible flow the density cancels and the relation reduces to A times V being constant, so a narrowing duct speeds the flow up.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.