Discussion

A boiler burns coal of \( 1.8 \) per cent sulphur at \( 400 \) t/day. Complete conversion gives a sulphur dioxide emission of

Answer: B

Correct answer: 14.4 t/day

The sulphur burnt is

\[ 400 \times 0.018 = 7.2 \text{ t/day} \]

and every atom of sulphur, of mass 32, becomes a molecule of sulphur dioxide, of mass 64, so the mass doubles:

\[ 7.2 \times \frac{64}{32} = 14.4 \text{ t/day} \]

The 7.2 t/day answer stops at the sulphur and forgets the oxygen picked up in combustion - the commonest error in this calculation.

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