Discussion
Catalytic oxidation at \( 350 \) degrees replaces thermal oxidation at \( 820 \) degrees. For a gas entering at \( 40 \) degrees, the temperature rise required falls by
Answer: D
The rises are \( 780 \) and \( 310 \) degrees, so the reduction is \( (780-310)/780 = 0.603 \). The fuel saving is close to that proportion, which is what justifies the catalyst's cost and its vulnerability to poisoning.
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