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A packed tower needs \( 6.4 \) transfer units with a height of a transfer unit of \( 0.55 \) m. The packed height required is

  • A.3.52 m
  • B.11.6 m
  • C.6.95 m
  • D.0.086 m

Answer: A

The height is the product, \( 6.4 \times 0.55 = 3.52 \) metres. A more efficient packing reduces the height of a transfer unit without changing the number of units, which is fixed by the difficulty of the separation itself.

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