Discussion
Gauss's law states that the flux of \( \mathbf{D} \) out of any closed surface equals
Answer: A
Written \( \oint_s \mathbf{D} \cdot d\mathbf{s} = Q_{enc} \), it involves the flux density and so needs no permittivity on the right. Expressed in terms of the field intensity instead, the permittivity appears as a divisor on the charge.
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