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A sphere of radius 2 m carries a uniform surface charge density of 1 nC/m². The total charge is about

  • A.12.6 nC
  • B.25.1 nC
  • C.201 nC
  • D.50.3 nC

Answer: D

Correct answer: 50.3 nC

\[ Q = \sigma \times 4\pi r^2 = 1 \times 4\pi \times 4 = 50.3\ \mathrm{nC}. \] The surface area of a sphere of radius 2 m is \( 16\pi \), or 50.3 square metres, so the numbers coincide here because the density is one nanocoulomb per square metre.

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