Discussion
A solid sphere of radius 1 m carries a uniform volume charge density of 3 nC/m³. The field at its surface is about
Answer: A
Correct answer: 113 V/m
First the charge: \[ Q = \rho \times \tfrac{4}{3}\pi r^3 = 3 \times 4.19 = 12.57\ \mathrm{nC}. \] Then the field at the surface, where the sphere acts as a point charge at its centre: \[ E = \frac{Q}{4\pi\varepsilon_0 r^2} = \frac{12.57 \times 10^{-9}}{1.113 \times 10^{-10}} = 113\ \mathrm{V/m}. \]
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