Discussion
How many diagonals does a pentagon have?
Answer: B
A polygon with \( n \) sides has
\[ \frac{n(n-3)}{2} \text{ diagonals} \]
\[ \frac{5(5-3)}{2} = \frac{10}{2} = 5 \]
Each vertex joins to all but itself and its two neighbours, and the division by 2 avoids counting each diagonal from both ends.
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