Discussion
The two corresponding angles formed by the intersection of two parallel lines by a transversal are \((3x - 20^\circ)\) and \((5x - 60^\circ)\). Then, the value of \((4x + 30^\circ)\) is :
Answer: C
The value of \((4x + 30^\circ)\) is 110°.
Corresponding angles formed by a transversal across parallel lines are equal:
\[ \begin{aligned} 3x - 20^\circ &= 5x - 60^\circ \\ 2x &= 40^\circ \\ x &= 20^\circ \end{aligned} \]
So \(4x + 30^\circ = 80^\circ + 30^\circ = 110^\circ\). Treating the angles as supplementary instead (adding to 180°) gives x = 32.5° and a different value.
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