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A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius r cm as shown in the figure. The side of the dodecagon is d cm. All the triangles (numbered 1 to 12) in the figure are used to form squares of side r cm and each numbered triangle is used only once to form a square.

The number of squares that can be formed and the number of triangles required to form each square, respectively, are:

Note: The figure shown is representative.

Regular dodecagon in a dashed circle, cut into 12 numbered triangles: nine meeting at the centre (1 to 9) and three thin triangles (10, 11, 12) along the edge; one side is labelled d.

  • A.3; 4
  • B.4; 3
  • C.3; 3
  • D.3; 2

Answer: A

The answer is 3 squares, with 4 triangles each.

The dodecagon is made of 12 central triangles with apex angle 30 degrees, so its area is

\[ 12 \times \tfrac{1}{2} r^2 \sin 30^{\circ} = 3r^2, \]

exactly three squares of side r. Twelve triangles shared among 3 squares means 4 per square.

The pieces do fit that way. Triangles 1, 4 and 7 are equilateral with side r (area \(\frac{\sqrt{3}}{4}r^2\)), each thin edge triangle 10, 11, 12 has area \(\frac{2 - \sqrt{3}}{4}r^2\), and the six 30-degree triangles have area \(\frac{1}{4}r^2\) each. One equilateral, one thin and two 30-degree triangles total \(r^2\). 4 squares would need more area than the dodecagon has, and 3 or 2 triangles per square would leave pieces over.

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