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The force between two identical solid spheres each of radius r kept in contact is F . If the distance of their centres is made 4r, then the force between them is

  • A.\(\frac{F}{2}\)
  • B.\(\frac{F}{4}\)
  • C.\(\frac{F}{8}\)
  • D.\(\frac{F}{16}\)
  • E.\(\frac{F}{24}\)

Answer: B

The force becomes \(\frac{F}{4}\).

Uniform spheres attract as if their masses were at their centres. In contact, the centres are 2r apart; the new separation is 4r, twice as far. Gravitational force varies as the inverse square of the distance:

\[ F' = F\left(\frac{2r}{4r}\right)^{2} = \frac{F}{4} \]

The trap is to take the original distance as r (the radius) instead of 2r, which gives \(\frac{F}{16}\). \(\frac{F}{2}\) forgets to square the ratio.

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