Discussion
A gyro with angular momentum \( I\omega = 0.5 \ \mathrm{kg\,m^2/s} \) is subjected to a torque of \( 0.02 \ \mathrm{N\,m} \). The precession rate is
Answer: B
Correct answer: 0.04 rad/s
Precession rate is the applied torque divided by the angular momentum:
\[ \Omega = \frac{T}{I\omega} = \frac{0.02}{0.5} = 0.04\ \mathrm{rad/s} \]
The inverse dependence on angular momentum is what makes a fast, heavy rotor a good reference: the same disturbing torque produces less precession. It is also why a gyro whose rotor is slowing becomes progressively less reliable, drifting faster as its momentum falls.
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