Discussion
Find the H.C.F. of
\(2^{2}\times 3^{2}\times 7^{2},2\times 3^{4} \times 7\)
Answer: B
The H.C.F. takes the lowest power of each shared prime.
\[ 2^{2} \cdot 3^{2} \cdot 7^{2} \quad\text{and}\quad 2 \cdot 3^{4} \cdot 7 \]
\[ \text{H.C.F.} = 2^{1} \cdot 3^{2} \cdot 7^{1} = 126 \]
The L.C.M. would take the highest powers instead.
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