Discussion
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
Answer: D
The number is 8 more than a common multiple of all four.
\[ 12 = 2^{2}\cdot 3, \ 15 = 3\cdot 5, \ 20 = 2^{2}\cdot 5, \ 54 = 2\cdot 3^{3} \]
\[ \text{L.C.M.} = 2^{2} \cdot 3^{3} \cdot 5 = 540 \]
\[ 540 + 8 = 548 \]
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