Discussion
A number when divided by 893 the remainder is 193. What will be the remainder when it is divided by 47?
Answer: B
\[ 893 = 19 \times 47 \]
So \( N = 893k + 193 \) is a multiple of 47 plus 193, and only 193 matters:
\[ 193 = 47 \times 4 + 5 \]
The remainder is 5. This works because 47 divides the original divisor.
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