Discussion
An aeroplane when 900 m high passes vertically above another aeroplane at an instant when their angles of elevation at same observing point are 60° and 45° respectively. Approximately, how many meters higher is the one than the other?
Answer: A
Both aircraft are on the same vertical line, so they share one horizontal distance \( d \) from the observer.
For the upper plane at 900 m, elevation 60°:
\[ \tan 60^{\circ} = \frac{900}{d} \quad\Longrightarrow\quad d = \frac{900}{\sqrt{3}} = 300\sqrt{3} = 519.6 \text{ m} \]
For the lower plane, elevation 45°:
\[ h = d\tan 45^{\circ} = 519.6 \text{ m} \]
\[ \text{difference} = 900 - 519.6 = 380.4 \approx 381 \text{ m} \]
The steeper 60° sighting must belong to the higher aircraft, which fixes which angle goes with which plane.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development