Discussion
From a tower of 80 m high, the angle of depression of a bus is 30°. How far is the bus from the tower?
Answer: C
The angle of depression from the tower top equals the angle of elevation of the top from the bus, so the 80 m height lies opposite the \( 30^{\circ} \).
\[ \tan 30^{\circ} = \frac{80}{d} \quad\Longrightarrow\quad d = \frac{80}{\tan 30^{\circ}} = 80\sqrt{3} \]
\[ d = 80 \times 1.73 = 138.4 \text{ m} \]
At \( 30^{\circ} \) the ground distance is always \( \sqrt{3} \) times the height, so it must exceed 80 m - a useful sanity check before computing.
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