Discussion
If a vertical pole 6 m high has a shadow of length 2 √3 metres, find the angle of elevation of the sun.
Answer: D
The pole and its shadow are the two legs of the triangle formed by the sun's ray.
\[ \tan\theta = \frac{6}{2\sqrt{3}} = \frac{3}{\sqrt{3}} = \frac{3\sqrt{3}}{3} = \sqrt{3} \]
\[ \theta = 60^{\circ} \]
Rationalising \( \tfrac{3}{\sqrt{3}} \) to \( \sqrt{3} \) is the step that makes the standard angle visible; left as a decimal it reads 1.732, which is the same thing.
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