Discussion
When the sun is 30º above the horizontal, Find the length of shadow cast by a building 50m high.
Answer: A
The building is opposite the \( 30^{\circ} \) altitude and the shadow is the base.
\[ \tan 30^{\circ} = \frac{50}{s} \quad\Longrightarrow\quad s = \frac{50}{\tan 30^{\circ}} \]
\[ s = 50\sqrt{3} \approx 86.6 \text{ m} \]
A low sun casts a long shadow, so the answer must exceed the 50 m height - a quick check that the division went the right way round.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development