Discussion
The angle of elevation of the top of a tower from a point 30 m from its base on level ground is 60 degrees. What is the height of the tower ?
Answer: C
Correct answer: \(30\sqrt{3}\) m
The height and the base distance are the opposite and adjacent sides of the angle of elevation.
\[\tan 60^\circ = \frac{h}{30} \quad\Longrightarrow\quad h = 30\tan 60^\circ = 30\sqrt{3} \approx 51.96 \text{ m}\]
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