Discussion
Two men stand on opposite sides of a tower. They measure the angles of elevation of the top of the tower as \( 30^{\circ} \) and \( 45^{\circ} \) respectively. If the height of the tower is 50 m, find the distance between the two men. (Take \( \sqrt{3} = 1.732 \))
Answer: B
The men are on opposite sides, so the tower's foot lies between them and their distances add.
\[ d_{30} = \frac{50}{\tan 30^{\circ}} = 50\sqrt{3} = 50 \times 1.732 = 86.6 \text{ m} \]
\[ d_{45} = \frac{50}{\tan 45^{\circ}} = 50 \text{ m} \]
\[ \text{distance apart} = 86.6 + 50 = 136.6 \approx 136.5 \text{ m} \]
The man at \( 30^{\circ} \) stands further off; the steeper the angle, the closer the observer.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development