Discussion
If the shadow of a tree is 16 meter when elevation of Sun is 60°, then the height of the tree is :
Answer: C
The height of the tree is \(16\sqrt{3}\) meter.
The tree, its shadow and the Sun's ray form a right triangle in which the angle of elevation is 60°:
\[ \begin{aligned} \tan 60^{\circ} &= \frac{h}{16} \\ h &= 16\sqrt{3} \approx 27.7 \text{ m} \end{aligned} \]
\(16/\sqrt{3}\) is the answer for an elevation of 30°, where the tree would be shorter than its shadow. 16 m would need an elevation of 45°, and 8 m is half the shadow, which corresponds to no standard angle.
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