Discussion
The ratio of the height and shadow of a tower is \(\sqrt{3} : 1\). Then the angle of elevation from the end point of the shadow top of the tower is (shadow is to be considered at bottom level of the tower)
Answer: C
The angle of elevation is 60°.
From the end of the shadow, the tower's height is the opposite side and the shadow the adjacent side:
\[ \begin{aligned} \tan\theta &= \frac{\text{height}}{\text{shadow}} \\ &= \frac{\sqrt{3}}{1} \end{aligned} \]
Since \(\tan 60^\circ = \sqrt{3}\), the angle is 60°. 30° would need the ratio \(1 : \sqrt{3}\), the reverse, and 45° would need a shadow equal to the height.
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