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In human, hypertrichosis is inherited as Y-linked trait. If a man marries a normal woman, which of the following types of offspring may they have ?

  • A.All sons and daughters will have hypertrichosis
  • B.All sons will have hypertrichosis but none of the daughters.
  • C.Only half of their sons will have hypertrichosis but none of the daughters
  • D.None of the children will have hypertrichosis.

Answer: B

The answer is that all sons will have hypertrichosis but none of the daughters.

A Y-linked (holandric) gene is carried only on the Y chromosome, which passes from father to every son and to no daughter. An affected father therefore passes the trait to all his sons, and his daughters, who receive his X chromosome, are unaffected. The mother, having no Y chromosome, contributes nothing to the trait.

Daughters cannot be affected, which rules out the first option. 'Half the sons' would fit an X-linked gene from a carrier mother, not a Y-linked gene from the father, and 'none of the children' ignores that every son inherits his father's Y.

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