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The wavelength of hydrogen spectrum known as Balmer series is given by :

  • A.\(\frac{1}{\lambda} = \left(\frac{1}{4^{2}} - \frac{1}{n^{2}}\right)R_{H}\) n = 5, 6, 7 .....
  • B.\(\frac{1}{\lambda} = \left(\frac{1}{3^{2}} - \frac{1}{n^{2}}\right)R_{H}\) n = 4, 5, 6 .....
  • C.\(\frac{1}{\lambda} = \left(\frac{1}{2^{2}} - \frac{1}{n^{2}}\right)R_{H}\) n = 3, 4, 5 .....
  • D.\(\frac{1}{\lambda} = \left(\frac{1}{1} - \frac{1}{n^{2}}\right)R_{H}\) n = 2, 3, 4 .....

Answer: C

The Balmer series is \(\frac{1}{\lambda} = \left(\frac{1}{2^{2}} - \frac{1}{n^{2}}\right)R_{H}\), n = 3, 4, 5 ...

The Balmer lines are transitions that end on the n = 2 level of hydrogen. They lie in the visible region: n = 3 to 2 is the red H-alpha line at 656 nm, and the series converges at about 365 nm.

The other options are the other series: lower level 1 is the Lyman series (ultraviolet), lower level 3 the Paschen series and lower level 4 the Brackett series (both infrared).

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