Discussion
A distant star has its surface temperature of about 2898 K. The wavelengths of light radiation which has maximum intensity emitted from these stars i.e. \(\lambda_{max}\) =
Answer: B
The peak wavelength is 1000 nm.
Wien's displacement law gives the wavelength of maximum emission of a black body:
\[ \begin{aligned} \lambda_{max} &= \frac{b}{T} = \frac{2.898 \times 10^{-3}\ \text{m K}}{2898\ \text{K}} \\ &= 10^{-6}\ \text{m} \end{aligned} \]
That is 1000 nm, in the near infrared. The temperature was chosen so the numbers cancel.
289.8 nm would need a star ten times hotter, and 10000 nm a body ten times cooler; 550 nm is the peak of the Sun, at about 5800 K.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development