Discussion
Occupants generate carbon dioxide at \( 0.018 \ \mathrm{m^3/h} \) each. To hold the indoor excess to \( 0.0006 \) by volume above outdoor, the outdoor air needed per person is
Answer: D
Correct answer: \( 30 \ \mathrm{m^3/h} \)
The required flow is the generation rate divided by the permitted excess concentration:
\[ Q = \frac{G}{\Delta C} = \frac{0.018}{0.0006} = 30\ \mathrm{m^3/h} \]
An excess of 0.0006 by volume is 600 parts per million, which with a typical outdoor value of about 400 gives an indoor level near 1000 ppm - the figure commonly used as a ventilation guideline. The calculation is what lies behind that number rather than any direct toxicity of carbon dioxide.
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