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A gas heater emits carbon monoxide at \( 60 \ \mathrm{mg/h} \) into a \( 30 \ \mathrm{m^3} \) kitchen ventilated at \( 15 \ \mathrm{m^3/h} \). The steady concentration is

  • A.\( 4.0 \ \mathrm{mg/m^3} \)
  • B.\( 2.0 \ \mathrm{mg/m^3} \)
  • C.\( 0.5 \ \mathrm{mg/m^3} \)
  • D.\( 1800 \ \mathrm{mg/m^3} \)

Answer: A

Correct answer: \( 4.0 \ \mathrm{mg/m^3} \)

At steady state:

\[ C = \frac{G}{Q} = \frac{60}{15} = 4.0\ \mathrm{mg/m^3} \]

The room volume of 30 m\(^3\) is not needed - it governs how quickly this level is reached, not the level itself. The low ventilation rate is what produces the high concentration: at 60 m\(^3\)/h the same appliance would give 1.0 mg/m\(^3\), which is why unvented combustion in a poorly ventilated kitchen is dangerous.

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