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The maximum efficiency an induction motor can reach, ignoring every loss but rotor copper loss, is

  • A.\( 1 - s \)
  • B.\( s \)
  • C.\( 1/(1 - s) \)
  • D.\( 1 + s \)

Answer: A

Since a fraction \( s \) of the air gap power is lost in the rotor, at best \( 1 - s \) reaches the shaft. A machine held at fifty per cent slip therefore cannot exceed fifty per cent efficiency however good the rest of it is.

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